Thinking Functionally with Haskell (3 page)

BOOK: Thinking Functionally with Haskell
7.86Mb size Format: txt, pdf, ePub
ads

that sorts the list of runs into descending order of count (the first component of each element). For example,
sortRuns [(2,"be"),(1,"not"),(1,"or"),(2,"to")]

= [(2,"be"),(2,"to"),(1,"not"),(1,"or")]

The next step is simply to take the first
n
elements of the result. For this we need a function
take :: Int -> [a] -> [a]

so that
take n
takes the first
n
elements of a list of things. As far as
take
is concerned it doesn’t matter what a ‘thing’ is, which is why there is an
a
in the type signature rather than
(Int,Word)
. We will explain this idea in the next chapter.

The final steps are just tidying up. We first need to convert each element into a string so that, for example,
(2,"be")
is replaced by
"be 2\n"
. Call this function
showRun :: (Int,Word) -> String

The type
String
is a predeclared Haskell type synonym for
[Char]
. That means
map showRun :: [(Int,Word)] -> [String]

is a function that converts a list of runs into a list of strings.

The final step is to use a function

concat :: [[a]] -> [a]

that concatenates a list of lists of things together. Again, it doesn’t matter what the ‘thing’ is as far as concatenation is concerned, which is why there is an
a
in the type signature.

Now we can define

commonWords :: Int -> Text -> String

commonWords n = concat . map showRun . take n .

sortRuns . countRuns . sortWords .

words . map toLower

The definition of
commonWords
is given as a pipeline of eight component functions glued together by functional composition. Not every problem can be decomposed into component tasks in quite such a straightforward manner, but when it can, the resulting program is simple, attractive and effective.

Notice how the process of decomposing the problem was governed by the declared types of the subsidiary functions. Lesson Two (Lesson One being the importance of functional composition) is that deciding on the type of a function is the very first step in finding a suitable definition of the function.

We said above that we were going to write a
program
for the common words problem. What we actually did was to write a functional definition of
commonWords
, using subsidiary definitions that we either can construct ourselves or else import from a suitable Haskell library. A list of definitions is called a
script
, so what we constructed was a script. The order in which the functions are presented in a script is not important. We could place the definition of
commonWords
first, and then define the subsidiary functions, or else define all these functions first, and end up with the definition of the main function of interest. In other words we can tell the story of the script in any order we choose. We will see how to compute with scripts later on.

1.4 Example: numbers into words

Here is another example, one for which we will provide a complete solution. The example demonstrates another fundamental aspect of problem solving, namely that a good way to solve a tricky problem is to first simplify the problem and then see how to solve the simpler problem.

Sometimes we need to write numbers as words. For instance

convert 308000 = "three hundred and eight thousand"

convert 369027 = "three hundred and sixty-nine thousand and

twenty-seven"

convert 369401 = "three hundred and sixty-nine thousand

four hundred and one"

Our aim is to design a function

convert :: Int -> String

that, given a nonnegative number less than one million, returns a string that represents the number in words. As we said above,
String
is a predeclared type synonym in Haskell for
[Char]
.

We will need the names of the component numbers. One way is to give these as three lists of strings:
> units, teens, tens :: [String]

> units = ["zero","one","two","three","four","five",

>
"six","seven","eight","nine"]

> teens = ["ten","eleven","twelve","thirteen","fourteen",

>
"fifteen","sixteen","seventeen","eighteen",
>
"nineteen"]

> tens = ["twenty","thirty","forty","fifty","sixty",

>
"seventy","eighty","ninety"]

Oh, what is the
>
character doing at the beginning of each line above? The answer is that, in a script, it indicates a line of Haskell code, not a line of comment. In Haskell, a file ending with the suffix
.lhs
is called a
Literate Haskell Script
and the convention is that every line in such a script is interpreted as a comment unless it begins with a
>
sign, when it is interpreted as a line of program. Program lines are not allowed next to comments, so there has to be at least one blank line separating the two. In fact, the whole chapter you are now reading forms a legitimate
.lhs
file, one that can be loaded into a Haskell system and interacted with. We won’t carry on with this convention in subsequent chapters (apart from anything else, it would force us to use different names for each version of a function that we may want to define) but the present chapter does illustrate
literate
programming in which we can present and discuss the definitions of functions in any order we wish.

Returning to the task in hand, a good way to tackle tricky problems is to solve a simpler problem first. The simplest version of our problem is when the given number
n
contains only one digit, so 0 ≤
n
< 10. Let
convert1
deal with this version. We can immediately define
> convert1 :: Int -> String

> convert1 n = units!!n

This definition uses the list-indexing operation
(!!)
. Given a list
xs
and an index
n
, the expression
xs!!n
returns the element of
xs
at position
n
, counting from 0. In particular,
units!!0 = "zero"
. And, yes,
units!!10
is undefined because
units
contains just ten elements, indexed from 0 to 9. In general, the functions we define in a script are
partial
functions that may not return well-defined results for each argument.

The next simplest version of the problem is when the number
n
has up to two digits, so 0 ≤
n
< 100. Let
convert2
deal with this case. We will need to know what the digits are, so we first define
> digits2 :: Int -> (Int,Int)

> digits2 n = (div n 10, mod n 10)

The number
div n k
is the whole number of times
k
divides into
n
, and
mod n k
is the remainder. We can also write
digits2 n = (n `div` 10, n `mod` 10)

The operators
`div`
and
`mod`
are infix versions of
div
and
mod
, that is, they come between their two arguments rather than before them. This device is useful for improving readability. For instance a mathematician would write
x
div
y
and
x
mod
y
for these expressions. Note that the back-quote symbol
`
is different from the single quote symbol
'
used for describing individual characters.

Now we can define

> convert2 :: Int -> String

> convert2 = combine2 . digits2

The definition of
combine2
uses the Haskell syntax for
guarded equations
:
> combine2 :: (Int,Int) -> String

> combine2 (t,u)

>
| t==0
= units!!u
>
| t==1
= teens!!u
>
| 2<=t && u==0
= tens!!(t-2)
>
| 2<=t && u/=0
= tens!!(t-2) ++ "-" ++ units!!u
To understand this code you need to know that the Haskell symbols for equality and comparison tests are as follows:

==
(equals to)

/=
(not equals to)

<=
(less than or equal to)

These functions have well-defined types that we will give later on.

You also need to know that the conjunction of two tests is denoted by
&&
. Thus
a && b
returns the boolean value
True
if both
a
and
b
do, and
False
otherwise. In fact
(&&) :: Bool -> Bool -> Bool

The type
Bool
will be described in more detail in the following chapter.

Finally,
(++)
denotes the operation of concatenating two lists. It doesn’t matter what the type of the list elements is, so
(++) :: [a] -> [a] -> [a]

For example, in the equation

[sin,cos] ++ [tan] = [sin,cos,tan]

we are concatenating two lists of functions (each of type
Float -> Float
), while in
"sin cos" ++ " tan" = "sin cos tan"

we are concatenating two lists of characters.

The definition of
combine2
is arrived at by carefully considering all the possible cases that can arise. A little reflection shows that there are three main cases, namely when the tens part
t
is 0, 1 or greater than 1. In the first two cases we can give the answer immediately, but the third case has to be divided into two subcases, namely when the units part
u
is 0 or not 0. The order in which we write the cases, that is, the order of the individual guarded equations, is unimportant as the guards are disjoint from one another (that is, no two guards can be true) and together they cover all cases.

We could also have written
but now the order in which we write the equations is crucial. The guards are evaluated from top to bottom, taking the right-hand side corresponding to the first guard that evaluates to
True
. The identifier
otherwise
is just a synonym for
True
, so the last clause captures all the remaining cases.

combine2 :: (Int,Int) -> String

combine2 (t,u)

| t==0
= units!!u

| t==1
= teens!!u

| u==0
= tens!!(t-2)

| otherwise
= tens!!(t-2) ++ "-" ++ units!!u

There is yet another way of writing
convert2
:

convert2 :: Int -> String

convert2 n

| t==0
= units!!u

| t==1
= teens!!u

| u==0
= tens!!(t-2)

| otherwise
= tens!!(t-2) ++ "-" ++ units!!u
where (t,u)
= (n `div` 10, n `mod` 10)

This makes use of a
where
clause
. Such a clause introduces a
local
definition or definitions whose
context
or
scope
is the whole of the right-hand side of the definition of
convert2
. Such clauses are very useful in structuring definitions and making them more readable. In the present example, the
where
clause obviates the need for an explicit definition of
digits2
.

That was reasonably easy, so now let us consider
convert3
which takes a number
n
in the range 0 ≤
n
< 1000, so
n
has up to three digits. The definition is
> convert3 :: Int -> String

> convert3 n

>
| h==0
= convert2 t
>
| n==0
= units!!h ++ " hundred"

>
| otherwise
= units!!h ++ " hundred and " ++ convert2 t
>
where (h,t)
= (n `div` 100, n `mod` 100)
We break up the number in this way because we can make use of
convert2
for numbers that are less than 100.

Now suppose
n
lies in the range 0 ≤
n
< 1, 000, 000, so
n
can have up to six digits. Following exactly the same pattern as before, we can define
> convert6 :: Int -> String

> convert6 n

>
| m==0
= convert3 h
>
| h==0
= convert3 m ++ " thousand"

>
| otherwise
= convert3 m ++ " thousand" ++ link h ++

>
convert3 h

>
where (m,h)
= (n `div` 1000,n `mod` 1000)
There will be a connecting word ‘and’ between the words for
m
and
h
just in the case that 0 <
m
and 0 <
h
< 100. Thus
> link :: Int -> String

> link h = if h < 100 then " and " else " "

This definition makes use of a conditional expression

if then else

BOOK: Thinking Functionally with Haskell
7.86Mb size Format: txt, pdf, ePub
ads

Other books

Bound by Pleasure by Lacey Wolfe
Poe's Children by Peter Straub
Possession by Violetta Rand
Chapman's Odyssey by Paul Bailey
Revenant by Phaedra Weldon
Debt of Ages by Steve White
The Temporary Wife by Jeannie Moon